SAT / PSAT
SAT / PSAT Prep
History & Social Science
AP World History AP US History AP European History AP Human Geography AP US Government & Politics AP Psychology AP Macroeconomics AP Microeconomics
English
AP English Language & Composition AP English Literature & Composition
Math & Computer Science
AP Calculus AB/BC AP Precalculus AP Statistics AP Computer Science A AP Computer Science Principles
Sciences
AP Biology AP Chemistry AP Environmental Science AP Physics 1 AP Physics 2
World Languages & Arts
AP Spanish Language AP Art History AP Music Theory Start studying →
🐦 Unit 7 · Natural Selection 🗂 Flashcards 🗺 Cheat Sheet Essentials 🎨 Visual Review 📝 MC Practice FRQ Practice

AP Biology Unit 7 FRQ Practice

Practice a College Board-style free response question on Natural Selection. Write your response, then reveal the model answer to see exactly what earns each point.

← Back to Unit 7 hub
Free Response Question · Unit 7 · Hardy-Weinberg Equilibrium and Selection

In a population of 1,000 beetles, body color is determined by a single gene with two alleles: B (dark, dominant) and b (light, recessive). A survey finds 360 light-colored (bb) beetles in the population. Researchers assume the population is in Hardy-Weinberg equilibrium for this gene.

GenotypePhenotypeNumber observed (of 1,000)
BBDark?
BbDark?
bbLight360
A
Using the data and the Hardy-Weinberg equations, calculate the frequency of the recessive allele (q) and the dominant allele (p) in this population. Show your work.

✓ Model answer (earns the point)

The frequency of the bb genotype (q²) = 360/1000 = 0.36. So q = √0.36 = 0.6. Since p + q = 1, p = 1 − 0.6 = 0.4.

Why it scores: Correctly identifies q² = 0.36 from the observed bb frequency, correctly takes the square root to find q = 0.6, AND correctly uses p + q = 1 to find p = 0.4. Showing each step explicitly earns full credit even if presented slightly differently.
B
Using your answer from Part A, calculate the expected number of heterozygous (Bb) beetles in this population of 1,000, assuming Hardy-Weinberg equilibrium.

✓ Model answer (earns the point)

The heterozygous frequency is 2pq = 2(0.4)(0.6) = 0.48. In a population of 1,000, the expected number of Bb beetles is 0.48 × 1,000 = 480 beetles.

Why it scores: Correctly calculates 2pq using the p and q values from Part A, AND correctly multiplies that frequency by the total population size (1,000) to get a count (480), not just a frequency.
C
A new predator moves into the beetles' habitat and preferentially eats light-colored (bb) beetles because they are easier to spot against the dark soil. Predict how the allele frequencies of B and b will change over the next several generations, and explain why, in terms of natural selection.

✓ Model answer (earns the point)

The frequency of the b allele will decrease, and the frequency of the B allele will increase over successive generations. Because the predator selectively removes light-colored (bb) individuals before they can reproduce, those individuals contribute fewer b alleles to the next generation's gene pool. Dark-colored individuals (BB and Bb) survive and reproduce at a higher relative rate, passing on more B alleles. This is natural selection: a heritable trait (color, determined by genotype) is affecting differential reproductive success in a way directly tied to the new selective pressure (the predator), shifting allele frequencies away from Hardy-Weinberg equilibrium over time.

Why it scores: Correctly predicts the direction of allele frequency change for BOTH alleles, AND explains the mechanism (bb individuals removed before reproducing → fewer b alleles passed on), AND explicitly names this as natural selection acting on heritable variation.

How to score points on AP Biology FRQs