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🪐 Unit 6 · Energy and Momentum of Rotating Systems 🗂 Flashcards 🗺 Cheat Sheet Essentials 🎙 Podcast 🎨 Visual Review 📝 MC Practice FRQ Practice

AP Physics 1 Unit 6 Essentials

The must-know terms and big ideas for Unit 6: Energy and Momentum of Rotating Systems. Rotational KE, angular momentum, conservation, rolling, and orbits.

← Back to Unit 6 hub
Big Idea 1
Rotation has its own energy and momentum
Rotating objects carry rotational KE (K = ½Iω²) AND angular momentum (L = Iω) in addition to any translational quantities. A rolling ball has both forms of energy at once. Torque does work just like force does (W = τΔθ), and angular impulse changes angular momentum just like linear impulse changes linear momentum (J_ang = τΔt = ΔL).
Rotational KE Angular Momentum Work and Impulse
Big Idea 2
Angular momentum is conserved when no external torque acts
If a system can change its rotational inertia without any external torque, its angular velocity adjusts so that L = Iω stays constant. Pull mass closer to the axis → I decreases → ω increases. That's why figure skaters spin faster when they pull in their arms, and why neutron stars (collapsed massive stars) can spin hundreds of times per second.
Conservation of L No External Torque L = Iω
Big Idea 3
Rolling objects share energy between translation and rotation
A rolling object has K_total = ½mv² + ½Iω². When it rolls down a ramp, gravitational PE (mgh) splits between linear KE and rotational KE. Objects with higher rotational inertia (per unit mass) put more energy into spinning, so they translate slower. That's why a solid disk beats a hoop down a ramp, even when they have the same mass and radius.
Rolling Motion v_cm = rω Race Down a Ramp
Angular Momentum (L)
The rotational analog of linear momentum. For a rigid body: L = Iω. Units: kg·m²/s. A vector quantity, just like linear momentum. The central concept of Unit 6.
Foundation
Rolling Motion
Motion combining translation (the center of mass moves) AND rotation (the object spins). A ball rolling down a hill, a tire on a moving car. Rolling objects have both translational and rotational KE.
Foundation
Rotational Kinetic Energy
K_rot = ½Iω². The KE an object has because it's rotating. Same form as ½mv², just with rotational analogs. Adds to any translational KE the object also has.
6.1 Rotational KE
Total Kinetic Energy
K_total = K_trans + K_rot = ½mv² + ½Iω². For a rolling object, both contribute. For a sliding object (not rotating), only the translational part counts. For a spinning top in place, only the rotational part.
6.1 Rotational KE
Energy Conservation in Rotation
Same as for linear motion (Unit 3), but include the rotational KE term. For a rolling object: K_trans_i + K_rot_i + U_i = K_trans_f + K_rot_f + U_f, when no non-conservative forces dissipate energy.
6.1 Rotational KE
Comparing KE of Rolling Objects
For two objects with the same m, R, and v, the one with HIGHER rotational inertia has MORE total KE (extra goes into spinning). A hoop and a disk rolling at the same speed have different total KEs.
6.1 Rotational KE
Work Done by Torque
W = τ·Δθ (when torque is constant). The rotational analog of W = F·d. Units: joules (J), same as any work or energy. Torque acting over an angular displacement transfers energy.
6.2 Torque and Work
Rotational Work-Energy Theorem
W_net = ΔK_rot = ½Iω_f² − ½Iω_i². The net work done by torques equals the change in rotational KE. The rotational analog of W_net = ΔK from Unit 3.
6.2 Torque and Work
Rotational Power
P = τω (for constant torque and constant angular velocity). The rotational analog of P = Fv. How fast torque is doing rotational work. Units: watts (W = J/s).
6.2 Torque and Work
Energy Transfer via Torque
When a motor applies torque to spin a wheel, it does rotational work. If torque and angular velocity are in the same direction, the motor adds energy to the wheel. Opposite directions = brake (removes energy).
6.2 Torque and Work
Angular Momentum of a Rigid Body
L = Iω. The rotational momentum of a spinning object. Larger I or larger ω = more L. Direction follows the right-hand rule (curl fingers in direction of rotation, thumb points along L).
6.3 Angular Momentum
Angular Momentum of a Point Mass
L = mvr_⊥, where r_⊥ is the perpendicular distance from the rotation axis to the line of motion. A car driving in a straight line has angular momentum about any axis NOT on its line of motion.
6.3 Angular Momentum
Angular Impulse
J_ang = τ·Δt. The rotational analog of linear impulse. Torque applied over time. Units: N·m·s = kg·m²/s (same as angular momentum, since J_ang = ΔL).
6.3 Angular Momentum
Angular Impulse-Momentum Theorem
J_ang = ΔL. The angular impulse on a system equals its change in angular momentum. The rotational analog of J = Δp from Unit 4. Area under a torque vs. time graph equals ΔL.
6.3 Angular Momentum
Conservation of Angular Momentum
If no net external TORQUE acts on a system, total angular momentum stays constant: L_i = L_f. The most important principle in Unit 6. (Note: external FORCES through the axis don't matter — only external TORQUES.)
6.4 Conservation of L
Closed (Isolated) System
For angular momentum: a system with no external torque acting. The internal interactions (parts pushing or pulling each other) come in equal/opposite pairs that cancel out — they can't change total L.
6.4 Conservation of L
Figure Skater Effect
The classic demonstration of L conservation: a skater pulls in her arms, reducing her rotational inertia I. With no external torque, L = Iω stays constant, so ω must INCREASE. Smaller I = larger ω.
6.4 Conservation of L
Neutron Star Formation
A massive star (large I, slow rotation) collapses to a neutron star (tiny I, very fast rotation). By conservation of L: as I drops dramatically, ω must rise dramatically. Neutron stars can rotate hundreds of times per second.
6.4 Conservation of L
Internal vs External Torques
Internal torques (between parts of a system) cancel by Newton's third law and don't change the system's total L. Only EXTERNAL torques (from outside the system) can change L. This is why the figure skater's arm movements don't change her L.
6.4 Conservation of L
Rolling Without Slipping
The condition v_cm = rω, where v_cm is the center-of-mass velocity and r is the object's radius. At the point of contact, the surface and the object have ZERO relative velocity — no sliding.
6.5 Rolling
Rolling With Slipping
When v_cm ≠ rω — the object is rolling AND sliding. Like a car peeling out: wheels spinning fast (large ω·r), car barely moving (small v_cm). The point of contact has nonzero velocity relative to the road.
6.5 Rolling
Rolling Down an Incline
Use energy conservation: mgh = ½mv² + ½Iω². With v = rω (no slipping), solve for v. Different rotational inertias give different final speeds — solid disks beat hoops, which beat sliding (non-rotating) blocks.
6.5 Rolling
Hoop vs Disk vs Sphere
Race down an incline: a solid sphere beats a solid disk beats a hoop (assuming same m and R). The one with the smallest I/(mr²) ratio puts the least energy into rotation, leaving more for translation — and reaches the bottom faster.
6.5 Rolling
Total KE of a Rolling Object
K_total = ½mv² + ½Iω². For rolling without slipping (v = rω), this becomes K_total = ½mv² + ½I(v/r)² = ½v²(m + I/r²). Always more KE than a non-rotating object moving at the same v.
6.5 Rolling
Orbital Motion
A satellite orbiting Earth (or any object orbiting another) is in free fall under gravity. Gravity provides the centripetal force that keeps the satellite curving around the planet instead of flying off in a straight line.
6.6 Orbits
Orbital Speed
v_orbit = √(GM/r), where M is the mass of the central body and r is the orbital radius. Notice: it DOESN'T depend on the satellite's mass. A small and a large satellite at the same altitude orbit at the same speed.
6.6 Orbits
Orbital Period
T = 2πr/v_orbit. Time for one complete orbit. Closer orbits are faster (shorter T). The Moon orbits Earth every ~28 days; the International Space Station orbits every ~90 minutes (because it's much closer).
6.6 Orbits
Kepler's Third Law (qualitative)
T² is proportional to r³. Bigger orbits take much longer. Doubling the orbital radius multiplies the period by 2√2 ≈ 2.83. This is built into v_orbit = √(GM/r) — at larger r, v is smaller AND the orbital circumference is bigger, so T grows rapidly.
6.6 Orbits