A College Board-style free-response question on Unit 2: Force and Translational Dynamics. Work through each part, then reveal the model answer to see exactly what earns each point.
Three forces act on the block:
1. Gravity (F_g = mg) — straight down (toward the center of the Earth). Magnitude = 4 · 10 = 40 N.
2. Normal force (F_N) — perpendicular to the incline surface, pointing away from the surface (up and away from the incline).
3. Kinetic friction (F_k) — parallel to the incline surface, pointing UP the incline (opposite to the block's motion down the incline).
Tip: For incline problems, tilt your coordinate axes so one axis (x) is parallel to the incline and the other (y) is perpendicular. Then resolve gravity into components: F_g,x = mg·sin(θ) down the incline, and F_g,y = mg·cos(θ) into the incline.
Use tilted axes: x parallel to the incline (positive down the incline), y perpendicular to the incline.
Perpendicular direction (y): The block doesn't accelerate into or out of the surface, so ΣF_y = 0.
F_N − mg·cos(θ) = 0 → F_N = mg·cos(θ) = 4 · 10 · 0.87 = 34.8 N
Friction: F_k = μ_k · F_N = 0.20 · 34.8 = 6.96 N (pointing up the incline)
Parallel direction (x): Apply Newton's second law down the incline:
mg·sin(θ) − F_k = ma
4 · 10 · 0.50 − 6.96 = 4a
20 − 6.96 = 4a → a = 13.04 / 4 ≈ 3.26 m/s²
Answer: a ≈ 3.3 m/s² down the incline.
The student is partially correct but missing important details. They're right that sin(θ) increases at steeper angles (gravity's pull along the surface gets larger), but they ignored that the NORMAL FORCE — and therefore friction — DECREASES as the angle increases.
Calculate at θ = 60°: sin 60° ≈ 0.87, cos 60° = 0.50.
F_N = mg·cos(60°) = 4 · 10 · 0.50 = 20 N
F_k = μ_k · F_N = 0.20 · 20 = 4 N
a = g·sin(60°) − μ_k·g·cos(60°) = 10·0.87 − 0.20·10·0.50 = 8.7 − 1.0 = 7.7 m/s²
Compare to part B: a at 30° ≈ 3.3 m/s². At 60°, a ≈ 7.7 m/s². That's a ratio of 7.7/3.3 ≈ 2.3, not 2.0. So acceleration MORE than doubles — the student's reasoning was incomplete but underestimated the effect.
The reason: friction shrinks as cos(θ) decreases, so two effects amplify the acceleration at steeper angles.