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💧 Unit 8 · Fluids 🗂 Flashcards 🗺 Cheat Sheet Essentials 🎙 Podcast 🎨 Visual Review 📝 MC Practice FRQ Practice

AP Physics 1 Unit 8 Visual Review

A slide-by-slide walkthrough of all 4 topics in Fluids. Each slide covers the big idea, key definitions, and a worked example.

← Back to Unit 8 hub
Topic 8.1
Internal Structure and Density
Mass per unit volume, and what makes fluids different from solids

The Big Idea

Density (ρ = m/V) measures how tightly packed matter is. Water has ρ = 1000 kg/m³. Lead has ρ ≈ 11,300 kg/m³. Air has ρ ≈ 1.2 kg/m³. Fluids (liquids and gases) flow because their molecules aren't locked into a rigid pattern. Liquids hold their volume but flow to fit their container; gases expand to fill any container.

Key Facts

Density Formula
ρ = m/V. Units: kg/m³.
Water
1000 kg/m³ (= 1 g/cm³).
Specific Gravity
Ratio to water. Lead = 11.3, wood = 0.5–0.9.
Compressibility
Liquids: nearly incompressible. Gases: highly compressible.

Example

Find the density of an object

A metal cube has mass 2.7 kg and side length 0.10 m. What is its density?

Volume: V = (0.10)³ = 1.0 × 10⁻³ m³ (1 liter)

Density: ρ = m/V = 2.7 / (1.0 × 10⁻³) = 2700 kg/m³

That's the density of aluminum. Since 2700 > 1000, it sinks in water.

Topic 8.2
Pressure
Force per area, and how it changes with depth

The Big Idea

Pressure = Force / Area (P = F/A). Pressure is a scalar — it acts in ALL directions at a point in a fluid. The deeper you go in a fluid, the more weight is above you pushing down. So pressure rises with depth: P = P₀ + ρgh. At the same depth, the pressure is the same everywhere in a connected fluid (Pascal's principle).

Key Equations

Definition
P = F/A. Units: pascals (Pa = N/m²).
Atmospheric
P_atm ≈ 1.0 × 10⁵ Pa at sea level.
Hydrostatic
P = P₀ + ρgh.
Pascal's Principle
Pressure transmits equally through enclosed fluid.

Example

Pressure at the bottom of a pool

A pool is 2.0 m deep. What is the pressure at the bottom? (P_atm = 1.0 × 10⁵ Pa, ρ_water = 1000, g = 10)

P = P₀ + ρgh = 10⁵ + (1000)(10)(2.0) = 10⁵ + 2 × 10⁴ = 1.2 × 10⁵ Pa

That's about 20% above atmospheric pressure. Every 10 m of water depth adds another atmosphere of pressure.

Topic 8.3
Fluids and Newton's Laws (Buoyancy)
Why things float, sink, or hover

The Big Idea

Archimedes' principle: The buoyant force on an object equals the weight of the fluid it displaces. F_b = ρ_fluid · V_displaced · g. This comes from the pressure difference between top and bottom of the object (bottom is deeper, so higher pressure pushes up more than top pushes down). If F_b > weight, the object floats up. If F_b < weight, it sinks. For a floating object, F_b = mg exactly.

Key Facts

Buoyant Force
F_b = ρ_fluid · V_disp · g. Uses FLUID density.
Floating Rule
ρ_object < ρ_fluid → floats.
Sinking Rule
ρ_object > ρ_fluid → sinks.
Fraction Submerged
When floating: ρ_object / ρ_fluid.

Example

A wooden block floating in water

A wooden block has density 600 kg/m³ and volume 1.0 × 10⁻³ m³ (1 liter). What is its mass, and what fraction is submerged when it floats in water?

Mass: m = ρV = (600)(1.0 × 10⁻³) = 0.60 kg

Fraction submerged = ρ_object / ρ_fluid = 600 / 1000 = 0.60 (60%)

The block sits 60% under water and 40% above. Check: F_b = (1000)(0.6 × 10⁻³)(10) = 6.0 N = (0.60)(10) = mg ✓

Topic 8.4
Fluids and Conservation Laws (Flow)
Continuity and Bernoulli — mass and energy in moving fluids

The Big Idea

Flowing fluids obey two conservation laws. Continuity (mass conservation): A₁v₁ = A₂v₂. Whatever flows into a pipe must flow out, so a narrower pipe forces faster flow. Bernoulli (energy conservation): P + ½ρv² + ρgh = constant along a streamline. As one term grows, another must shrink. Fast-moving fluid has LOW pressure — that's how airplane wings produce lift.

Key Equations

Continuity
A₁v₁ = A₂v₂. Smaller pipe = faster.
Bernoulli
P + ½ρv² + ρgh = constant.
Flow Rate
Q = A·v. Units: m³/s.
Key Insight
Fast flow = low pressure.

Example

Water through a narrowing pipe

Water flows at 2.0 m/s through a pipe with cross-section 4.0 × 10⁻⁴ m². The pipe narrows to 1.0 × 10⁻⁴ m². What is the water's speed in the narrow section?

Continuity: A₁v₁ = A₂v₂ → (4.0 × 10⁻⁴)(2.0) = (1.0 × 10⁻⁴)·v₂

v₂ = (8.0 × 10⁻⁴) / (1.0 × 10⁻⁴) = 8.0 m/s

The water speeds up by a factor of 4 (matching the 4× area decrease). By Bernoulli, the pressure in the narrow section is LOWER than in the wide section.

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How to use this visual review

Take 2-3 minutes per slide. Read the Big Idea, then the key facts, then the worked example. Four slides total — one per topic.

The two most-tested ideas are buoyancy (8.3) and Bernoulli (8.4). Make sure you can solve a floating-object problem and a pipe-flow problem from start to finish.