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⏱️ Unit 5 · Kinetics 🏠 Unit Hub 🗂 Flashcards 🗺 Cheat Sheet Essentials 🎨 Visual Review 📝 MC Practice ✍️ SAQ Practice

AP Chemistry Unit 5 SAQ Practice

Practice a College Board-style short-answer question on Kinetics. Write your response, then reveal the model answer to see exactly what earns each point.

← Back to Unit 5 hub
Short Answer Question · Unit 5 · Reaction Mechanisms & Rate Law
The decomposition of ozone, 2O₃(g) → 3O₂(g), is proposed to occur through the following two-step mechanism:
StepElementary reactionRelative speed
1O₃ → O₂ + OSlow
2O₃ + O → 2O₂Fast
The experimentally determined rate law for the overall reaction is rate = k[O₃].
A
Verify that the two-step mechanism sums to the overall balanced equation, and identify any intermediate species.

✓ Model answer (earns the point)

Adding the two steps: (O₃ → O₂ + O) + (O₃ + O → 2O₂) gives 2O₃ → 3O₂ after canceling the O that appears as a product in Step 1 and a reactant in Step 2 — matching the overall balanced equation. The species O (atomic oxygen) is the intermediate, since it is produced in Step 1 and fully consumed in Step 2, never appearing in the overall equation.

Why it scores: Shows the addition of the two steps with the canceling species explicitly identified AND names O as the intermediate with a reason (produced then consumed).
B
Explain why the experimentally determined rate law, rate = k[O₃], is consistent with Step 1 being the rate-determining step.

✓ Model answer (earns the point)

Since Step 1 (O₃ → O₂ + O) is the slow, rate-determining step, the predicted rate law comes directly from its molecularity: rate = k[O₃], since O₃ is the only reactant in that elementary step. This matches the experimentally observed rate law exactly, which supports the validity of this proposed mechanism.

Why it scores: Explicitly derives the rate law from the rate-determining step's molecularity AND confirms it matches the given experimental rate law, rather than just restating that they match.
C
Sketch (in words) how the reaction energy profile for this two-step mechanism would differ from a single-step reaction, and identify which peak on the multistep profile would be higher.

✓ Model answer (earns the point)

Unlike a single-step reaction's profile (one smooth hump from reactants to products), this two-step mechanism's energy profile would show two separate peaks (one for each elementary step) with a dip between them representing the intermediate, O, at a local energy minimum. Because Step 1 is the slow, rate-determining step, it has the higher activation energy — its peak would be taller than the peak for Step 2, reflecting that Step 1 requires more energy to overcome and is therefore the bottleneck of the overall reaction.

Why it scores: Describes the two-peaks-with-a-dip structure (intermediate at a local minimum) AND correctly identifies that the rate-determining step's peak (Step 1) is the taller one, with a stated reason.

How to score points on SAQs