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🧬 Unit 6 · Gene Expression & Regulation 🗂 Flashcards 🗺 Cheat Sheet Essentials 🎨 Visual Review 📝 MC Practice FRQ Practice

AP Biology Unit 6 FRQ Practice

Practice a College Board-style free response question on Gene Expression & Regulation. Write your response, then reveal the model answer to see exactly what earns each point.

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Free Response Question · Unit 6 · The Lac Operon and Gene Regulation

The lac operon in E. coli contains genes needed to metabolize lactose. A repressor protein normally binds to the operator and blocks RNA polymerase from transcribing the operon's genes. Researchers grow E. coli in four different media and measure the relative transcription rate of the lac genes:

Growth mediumRelative transcription rate of lac genes
Glucose only (no lactose)Very low
Lactose only (no glucose)Very high
Glucose and lactoseLow
No glucose, no lactoseVery low
A
Using the data, explain why transcription of the lac genes is very low when only glucose is present. Describe the role of the repressor protein in your explanation.

✓ Model answer (earns the point)

When only glucose is present, there is no lactose to inactivate the lac repressor protein. The repressor therefore stays bound to the operator sequence, physically blocking RNA polymerase from binding the promoter and transcribing the structural genes. Since the cell already has glucose (its preferred energy source) and has no lactose to break down anyway, keeping the operon off conserves energy and resources that would otherwise be wasted making unneeded enzymes.

Why it scores: States that the repressor is bound to the operator when lactose is absent AND explains that this physically blocks RNA polymerase/transcription, AND connects this to the adaptive/energy-saving rationale for the cell.
B
Explain why the transcription rate is very high in lactose-only medium but only "low" (not very high) when BOTH glucose and lactose are present.

✓ Model answer (earns the point)

In lactose-only medium, lactose (via a metabolite) binds to and inactivates the repressor, so it releases from the operator and RNA polymerase can transcribe the lac genes at a high rate — the cell needs those enzymes to use lactose as its energy source. When BOTH glucose and lactose are present, the repressor is still inactivated by lactose, but the cell preferentially uses glucose. The presence of glucose lowers the activity of a separate activator protein (CAP) that normally boosts lac transcription, so even though the operon isn't fully repressed, it is transcribed at a much lower rate than when lactose is the only sugar available.

Why it scores: Correctly explains that lactose inactivates the repressor (allowing transcription) AND explains that the presence of glucose reduces transcription even when lactose is present (preferential use of glucose / reduced activator activity), accounting for the "low" but non-zero rate.
C
A mutation occurs in the operator region of the lac operon so that the repressor protein can no longer bind to it. Predict the effect of this mutation on transcription of the lac genes when the cell is grown in glucose-only medium (no lactose). Justify your prediction.

✓ Model answer (earns the point)

Transcription of the lac genes would occur even in glucose-only medium, despite the absence of lactose — the operon would be transcribed when it normally should be OFF. Normally, the repressor binds the operator (when lactose is absent) and blocks RNA polymerase from transcribing the operon. If the operator is mutated so the repressor can no longer bind it, RNA polymerase is no longer blocked and can transcribe the lac genes regardless of whether lactose is present. This produces lac enzymes the cell doesn't need, wasting energy and resources.

Why it scores: Correctly predicts that transcription occurs/increases despite no lactose being present, AND justifies the prediction by explaining that the repressor can no longer bind the (mutated) operator to block RNA polymerase, AND (bonus) notes the cost of producing unneeded enzymes.

How to score points on AP Biology FRQs